Question

A beam of X rays of wavelength 0.3nm is incident on a crystal and gives a first-order maximum when the glancing angle is 9 degree. find the atomic spacing​

Answer 1

Answer:

Explanation:

A beam of X rays of wavelength 0.3nm is incident on a crystal and gives a first-order maximum when the glancing angle is 9 degree. find the atomic spacing

Answer 2

Given:

$\lambda = 0.3nm\\sin \theta = 9\degree$ degree

To find:

Atomic spacing

Solution:

• A beam of X-rays of wavelength $\lambda$ when fall on a crystal whose atomic planes are separated by a distance d and the glancing angle  is $\theta$ , then the X-ray diffraction is given by :

         $2d sin\theta = n\lambda$

• When the X-ray wavelength in the crystal is known then the atomic spacing in the crystal can be easily determined. Hence this equation useful in determining the structure of the crystal.

• Rearranging the above equation :

        $d = \frac{\lambda}{2\times sin\theta }$  

       we know that ; $sin9 = 0.156$

       $\therefore d = \frac{0.3}{2\times 0.156} = 0.96nm$

• Therefore , the atomic spacing is 0.96nm (Answer)