Question

A beam pivoted at one side has a force of 5.0N acting vertically upwards. The beam is equilibrium what is the weight of the beam

Answer 1

Answer:

5 kg

Explanation:

Since the beam is in equilibrium, the forces acting on the beam in opposite directions must be equal

=> Downward force ( Gravitational force ) = Vertically upward force

=> Mass × acceleration = 5 N

Here acceleration is 'g'

=> M × g = 5 N

=> Weight = 5 kg

Answer 2

Answer:

ITS 2.0N

Explanation:

2 TIMES 5=10

10/5= 2

SO ITS 2.0 N