Question

A beautiful maiden, with beaming eyes, asks me which is the number, that multiplied by 3, then incresed by three fourths of the product, divided by 7, diminished by one third of the quotient, multiplied by itself, diminished by 52, the square root found, addition of 8 , division by 10 gives the number 2?

Answer 1

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Answer 2

Hey there!

Let the number be x

Now, going according to word of maiden ,

The number is multiplied by 3 and decreased by 3/4

So, x * 3 + 3/4 ( 3x )

= 21/4x

Then, divided by 7 and diminished by 1/3 of quotient,
21x/4 ÷ 7 = 3x/4

3x/4 - 1/3 ( 3x/4)

= 2/3 ( 3/4 ) x

= x/2

Multiplied by itself,

= x/2 * x/2

= x²/4

Now diminished by 52

= √ ( x²/4 - 52 )

Then added 8 , divided by 10

= [ √ ( x²/4 - 52 ) + 8 ] / 10

According to the question,


[ √ ( x²/4 - 52 ) + 8 ] / 10 = 2

√( x²/4 - 52 ) + 8 = 20

√(x²/4 -52 ) = 12

x²/4 - 52 = 144

x²/4 = 144 + 52

x²/4 = 196

(x/2)² = 14²

x/2 = 14

x = 2 * 14

x = 28 .

Therefore, The number is 28