Question

A bee sets out of its beehive, flies 15√3 m in the east, turns down, descends 12 m flying vertically downwards, then turns in the south, flies 9m and finally reaches a flower 5s after its sets out off its beehive. What is magnitude of average velocity vector ?​

Answer 1

Given:

A bee sets out of its beehive, flies 15√3 m in the east, turns down, descends 12 m flying vertically downwards, then turns in the south, flies 9m.

To find:

Average Velocity after 5 seconds?

Calculation:

The net displacement will be :

$\rm \: d = \sqrt{ {(15 \sqrt{3}) }^{2} + {12}^{2} + {9}^{2} }$

$\rm \implies\: d = \sqrt{ 675 + 144 + 81}$

$\rm \implies\: d = \sqrt{900}$

$\rm \implies\: d = 30 \: m$

Now, average velocity :

$\rm \: avg. \: v = \dfrac{30}{5}$

$\rm \implies\: avg. \: v = 6\: m {s}^{ - 1}$

So, average velocity is 6 m/s.