Question

A beg contain Rs 155 in the form of 1-rupee, 50-paise and 10-paise coins in the ratio of 3:5:7. Then the total number of coins are

=> 370

=> 400

=> 375

=>350

​

Answer 1

A bag contains Rs 155 in the form of 1-rupee, 50 - paise and 10-paise coins in the ratio of 3:5:7.

Let the ratio be x

So, No. of 1-rupee coins = 3x

Value of 3x 1-rupee coins = 3x

No. of 50-paisa coins = 5x

Value of 5x 50-paisa coins = 250x paisa = Rs.2.5x

No. of 10-paisa coins = 7x

Value of 7x 10-paisa coins = 70x paisa = Rs.0.7x

Now we are given that the total sum is rs.155

So,

No. of 1-rupee coins = 3x = 3*25 =75

No. of 50-paisa coins =5x= 5*25 = 125

No. of 10-paisa coins = 7x = 7*25 = 175

Hence There are 75,125 and 175 coins of 1-rupee, 50 - paise and 10-paise respectively.

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