a beg contain some coins of denomination 25paise, 50paise and ₹1 respectively, the no. of 50 paise coin is 5 times the no. of ₹1 coins and number of 25 paise ciins is twice the the no. 50 paise coins . if total amount of money in the bag is ₹72 , find the no. of coins of each denomination
Answers
Answer:
80
Step-by-step explanation:
A bag contains 25 paise and 50 paise coins whose total value is Rs 30. If the number of 25 paise coins is four times that of 50 paise coins, find the number of each type of coins. Thus, the number of 50 paise coins = x = 20, The number of 25 paise coins = 4x = 4 (20) =80.
Answer:
120 coins of 25 paise
60 coins of 50 paise
12 coin of 1 rupee .
explained 1) 1 rs coin or 100 paise coin
by using Ratio method no of coins are -:
25 paise : 50 paise : 100paise
5 :. 1 (given stat)
[ 10x :. 5 x :. 1x. (given statement in question conclusion) ]
after making their ration
25 paise : 50 paise : 100 pasis
no of coins. 10x : 5x : 1 x
given total amount is 72rs
25 × 10x = 250x paise
50×5x. =250x paise
100×1x = 100x paise
their sum is equal to 72 rs or 72×100= 7200 paise
_______
600__| 7200 | 12
0
means x is equal to 12
now in ration we have no. of coins
25 paise: 50paise : 100paise
10x. : 5x : 1x
putting x =12
for 25 paise coin 10×12= 120
50 paise coin 5 × 12 = 60
100 paise coin or 1 rs coin 1×12 = 12
if you will add their their valuues you will get 72 rs
( units must be same )
do let me know if my answer is correct.!