Question

A bell rings in a 5 hour 12 seconds, 5 hours 15 second, 5 hour 20 second, 5 hour 25 second and 5 hour 45 second and all ring at 5 am then what is second time when bell rings at same time

Answer 1

${\large\bf{\mid{\overline{\underline{Correct\:Question:-}}}\mid}}$

A bell rings in 5:12 seconds, 5:15 second, 5:20 second, 5:25 second and 5:45 second and all ring at 5 am. then what is second time when bell rings at same time ?

${\large\bf{\mid{\overline{\underline{Given:-}}}\mid}}$

• First bell ring at 5:12 am .
• Second bell ring at 5:15am
• Third bell ring at 5:20 am
• Fourh bell ring at 5:25 am
• Fifth bell ring at 5:45am .
• all 5 bell Together rings at = 5:00am.

$\Large\underline\mathfrak{Question}$

• at what time all 5 bells will ring again after 5 am. ?

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$\Large\underline{\underline{\sf{Solution}:}}$

→ in these type of Problems we will just Find LCM of all time intervals and than add into previous Same bells ring time .

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Lets Find LCM of 12,15,20,25 and 45 seconds.

we know that, The least common multiple (LCM) of any numbers is the smallest number that they both divide evenly into.

➥ 12 = 2 × 2 × 3

➥ 15 = 3 × 5

➥ 20 = 2 × 2 × 5

➥ 25 = 5 × 5

➥ 45 = 3 × 3 × 5 .

✪ LCM = 2 x 2 x 3 x 5 x 5 = 300 seconds .

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Now we know that,

⟿ 60 seconds = 1 minute

⟿ 1 second = (1/60) minutes

⟿ 300 seconds = (1/60)*300 = 5 minutes .

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Hence, all 5 bells will ring after a interval of 5 minutes .

➾ First time they bell together at = 5 am.

➾ Next time they bell together at = 5 am + 5 minutes = 5:00 + 5 minutes = 5:05AM .

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⛬ the second time when bell rings at same time is 5:05 AM ...

$\large\underline\textbf{Hope it Helps You.}$

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Extra Brainly Knowledge :----

If A•x^2 + B•x + C = 0 ,is any quadratic equation,

then its discriminant is given by;

D = B^2 - 4•A•C

• If D = 0 , then the given quadratic equation has real and equal roots.

• If D > 0 , then the given quadratic equation has real and distinct roots.

• If D < 0 , then the given quadratic equation has unreal (imaginary) roots.

Answer 2

${\huge{\boxed{\overline{\mid{\green{solution}}}}}}$

${\small{\boxed{\overline{\mid{\green{Lets\: Find\: LCM\: of\:}}}}}}$

》 12,15,20,25 and 45 seconds.

${\small{\boxed{\overline{\mid{\green{we\: know\: that,\:}}}}}}$

The least common multiple (LCM) of any numbers is the smallest number that they ${\huge{\boxed{\overline{\mid{\green{both\:divide\: evenly\: into.\:}}}}}}$

》12 = 2 × 2 × 3

》 15 = 3 × 5

》20 = 2 × 2 × 5 25 = 5 × 5

》45 = 3 × 3 × 5 .

 LCM = 2 x 2 x 3 x 5 x 5 = 300 seconds .

${\small{\boxed{\overline{\mid{\green{Now\: we \:know\: that\:}}}}}}$

》60 seconds = 1 minute

》1 second = (1/60) minutes

》300 seconds = (1/60)*300 = 5 minutes 

${\small{\boxed{\overline{\mid{\green{Hence,}}}}}}$

 all 5 bells will ring after a interval of 5 minutes .

》 First time they bell together at = 5 am.

》 Next time they bell together at = 5 am + 5 minutes = 5:00 + 5 minutes = 5:05AM

》the second time when bell rings at same time is 5:05 AM

${\huge{\boxed{\overline{\mid{\green{Ans\:5:05}}}}}}$