( a +bi ) - (c + di ) =
Answers
Answered by
0
Answer:
The standard form is
a
+
b
i
a
+
b
i
c
+
d
i
Multiply the numerator and the denominator by the conjugate of the denominator
(
a
+
b
i
c
+
d
i
)
⋅
(
c
−
d
i
c
−
d
i
)
=
(
a
+
b
i
)
(
c
−
d
i
)
(
c
+
d
i
)
(
c
−
d
i
)
=
a
c
−
a
d
i
+
c
b
i
−
b
d
i
2
c
2
−
c
d
i
+
c
d
i
−
d
2
i
2
Add like terms
=
a
c
+
(
c
b
−
a
d
)
i
−
b
d
i
2
c
2
−
d
2
i
2
i
2
=
−
1
=
a
c
+
(
c
b
−
a
d
)
i
−
b
d
(
−
1
)
c
2
−
d
2
(
−
1
)
=
a
c
+
(
c
b
−
a
d
)
i
+
b
d
c
2
+
d
2
=
a
c
+
b
d
+
(
c
b
−
a
d
)
i
c
2
+
d
2
=
a
c
+
b
d
c
2
+
d
2
+
(
c
b
−
a
d
)
i
c
2
+
d
2
=
a
c
+
b
d
c
2
+
d
2
+
c
b
−
a
d
c
2
+
d
2
i
Answered by
1
Answer:
a+bi-c-di
(a-c)+(bi-di)
Step-by-step explanation:
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