A bi convex lens of focal lenght 2/3 radius of curvature of surface. Calculate the refractive index of lens material?
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i think it is 1.75......
1/f=(n-1)[(1/R)+(1/R)]
f=2R/3 (given)
3/2R=(n-1)(2/R)
3/4=n-1
n=(3/4)+1=7/4=1.75
anamika6272:
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