A biased coin is tossed 6 times. The probability of heads on any toss is 0.3. Let X denote the number of heads that comes up. Find (i) P(x=2) (ii) P(x=3) and (iii) P(1< x ≤ 5).
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Answer:
P(x=2)
P(r)= ^n Crq^n-r p^r
P(x=2) 6C2(0.7)^6-2 (0.3)^2
= 6×0.7^4 ×0.3^2
= 0.129654
P(×=3)
P(r)= ^n Crq^n-r p^r
P(x=3) 6C3(0.7)^6-3 (0.3)^3
= 6×0.7^3 ×0.3^3
=0.055566
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