Question

A biased die has a probability of 1/4 of showing a 5, while the probability of any of 1, 2, 3, 4, or 6

turning up is the same . If three such dice are rolled, what is the probability of getting a sum of atleast

14 without getting a 6 on any die ?

Answer 1

according to my opinion, there is a probability of occuring- no.2 in 1st dice, no. 3 in 2nd dice and no. 4 in 3rd dice.