a biconcave lens has focal length f and intensity of light I passing through it. What will be the focal length and intensity for proportion of lenses obtained by cutting it vertically and horizontally?
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Answer:
If a symmetrical convex lens of focal length f is cut into two parts along the principal axis, then focal length of each part remains unchanged at f. If these two parts are joined with curved ends on one focal length of the combination is
2
f
. But joining two parts in opposite, net focal length becomes ∞.
(Net power) =0
From Lens maker formula
f
1
=(μ−1)⋅(
R
1
−
−R
1
)....(i)
f
1
1
=(μ−1)⋅(
R
1
−
∞
1
)....(ii)
Substituting the value, we get
f
1
=2f
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Answer:no other go... U must write by ur own.. can u understand my dears
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