Question

a biconvex lens made of a material of refractive index 1.5 has radius of curvature of its side equal to 0.5 m the power of lenses

Answer 1

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Answer 2

Answer:

The power of lenses is 2 Dioptre.

Explanation:

Given

Refractive index(μ)=1.5

Radius of curvature(R₁)=0.5 m and R₂= - 0.5m

Power of lens(P)=?

To find the power of the lens

Solution:

Using lens formula

$\frac{1}{f} =(Refractive index - 1) (\frac{1}{R1} -\frac{1}{R2} )$

1/f = μ-1(1/0.5+1/0.5)

⇒1/f=(1.5-1) (2+2)

⇒1/f=0.5×4

⇒f=1/2

⇒f=0.5 m

Now

Using the formula of power(P)

$P=\frac{1}{f}$

⇒1/0.5

⇒P=2D

Therefore, the power of the lenses is 2 Dioptre.