Question

a biconvex lens ( refractive index=1.5) of focal length 0.2 m acts as a divergent lens of power 1D when immersed in a liquid. find the refractive index of the liquid. ​

Answer 1

Answer:

New focal length

f=

1D

1

=1 m

f

1

=0.2 m.

So we have,

f

1

=(n−1)(

R

1

1

+

R

2

1

)

for biconvex lens

f

1

f

=

μ

2

−1

μ

1

−1

0.2

1

=

μ

2

−1

1.5−1

∴μ

2

=1.01

mark the answer as brainlist!!!