Question

A bicycle accelerates at 1.25 m/s/s to a velocity of 11.5 m/s in 5.00 s. Find the initial velocity of the bike.

Answer 1

U = Initial Velocity = 5.25 m/s

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Answer 2

To Find :–

The Final Velocity of the Bicycle .

Given :–

• Acceleration Produced → a = 1.25 m/s²

• Final Velocity → v = 11.5 m/s

• Time Taken → t = 5 or 5.00 s

We Know :–

First Equation of Motion :-

$\boxed{\bf{\bigstar\:v = u \pm at\:\bigstar}}$

Where :-

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration Produced
• t = Time Taken

Concept :–

• The Acceleration Produced will be Positive.

• The Initial Velocity of the cycle will be lesser than the final Velocity.

Solution :–

Using the First Equation of Motion and substituting the values in it , we get :-

Let the Initial Velocity be u.

$:\implies \bf{v = u \pm at} \\ \\ \\ :\implies \bf{v = u + at} \\ \\ \\ :\implies \bf{11.5 = u + 1.25 \times 5} \\ \\ \\ :\implies \bf{11.5 = u + 6.25} \\ \\ \\ :\implies \bf{11.5 - 6.25 = u} \\ \\ \\ :\implies \bf{5.25 = u} \\ \\ \\ :\implies \purple{\bf{u = 5.25 ms^{-1}}}$

Hence the Initial Velocity of the cycle is 5.25 m/s.