Question

A bicycle accelerates at 1 m/s-2 from an initial velocity of m/s-1 for 10 s. Find the distance moved by it during this interval of time.

Answer 1

Answer:

Distance ,S = 60m

Explanation: step by step explanation

intial velocity , u = 1 m/s

acceleration , a= 1  m/s ^2

time , t = 10s

By second equation of motion ,

S = ut+1/2at^2

so substitute the values

S= 1*10+1/2*1*10^2

= 10+1/2*1*100

= 10+50

= 60 m

so the distance moved during the tim interval is 60m

Hope you understand this !!!!!!