Question

A bicycle increase its velocity from 10km per hour to 15km per hour in 6sec calculate its acceleration

Answer 1

Answer:

The required acceleration is 0.23 m/s².

Explanation:

Given :

A bicycle increases its velocity from 10 km/hr to 15 km/hr in 6 sec.

To find :

the acceleration of the bicycle

Solution :

initial velocity, u = 10 km/hr

final velocity, v = 15 km/hr

time taken, t = 6 sec

We know,

1 km/hr = 5/18 m/s

So,

⇒ u = 10 kmph

⇒ u = 10 × 5/18

⇒ u = 50/18 m/s

⇒ v = 15 kmph

⇒ v = 15 × 5/18 m/s

⇒ v = 75/18 m/s

The acceleration is the rate of change of velocity.

$\longmapsto \tt a =\dfrac{v-u}{t}$

Substituting,

$\sf a=\dfrac{\dfrac{75}{18}-\dfrac{50}{18}}{6} \\\\ \sf a=\dfrac{\dfrac{75-50}{18}}{6} \\\\ \sf a=\dfrac{25}{18 \times 6} \\\\ \sf a=\dfrac{25}{108} \\\\ \sf a \approx 0.23 \ m/s^2$

Therefore, the acceleration of the bicycle is 0.23 m/s²