A bicycle increases it's velocity from 10km/h to 15kmph in 6 seconds. calculate it's acceleration.
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We are given that the initial velocity (u) of the bicycle was 10 km/h. Also, it's final velocity (v)becomes 15 km/h. Time taken (t) was 6 seconds.
We know,
Acceleration = Rate of Change of Velocity,
or mathematically,
a = (v-u)/t
where,
a stands for acceleration, v and u are the final and initial velocities respectively and t is for time taken.
or, a = (15 km/h - 10 km/h)/(6 s)
or, a = (5 km/h)/(6 s)
or, a = (25/18 m/s)/(6s)
or, a = (25/18 × 6) m/s²
or, a = 25/3 m/s²
(or, a ≈ 8.3 m/s²)
Therefore, acceleration was of approximately 8.3 m/s².
Note: We converted (km/h) to (m/s) by multiplying the speed value given in (km/h) with (5/18).
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