a bicycle increases its velocity from 10 km per hour to 15 km per hour in 6 second calculate its acceleration
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Answered by
2
Initial velocity =10km/hr.(u)
Final velocity =!15km/hr.(v)
Change in velocity =v-u=15km/hr-10km/hr=5km/hr.
Acceleration =v-u/t=5km/hr/6s
=5000m/60×60/6sec=0.2314m/sec^2
Final velocity =!15km/hr.(v)
Change in velocity =v-u=15km/hr-10km/hr=5km/hr.
Acceleration =v-u/t=5km/hr/6s
=5000m/60×60/6sec=0.2314m/sec^2
Answered by
1
u = 10 km/h = 25/9 m/s
v = 15 km/h = 25/6 m/s
Also, t is 6s
Acceleration is dv/dt....
which means
(change in velocity)/(Change in time)
or v-u/t
So, a = (25/6 - 25/9)/6
which is equal to ... 25/108 m/s^2
You should always given your answer is m/s^2 as this is the SI unit.....
(Of course, until said not to do so)
Feel free to ask any doubts
v = 15 km/h = 25/6 m/s
Also, t is 6s
Acceleration is dv/dt....
which means
(change in velocity)/(Change in time)
or v-u/t
So, a = (25/6 - 25/9)/6
which is equal to ... 25/108 m/s^2
You should always given your answer is m/s^2 as this is the SI unit.....
(Of course, until said not to do so)
Feel free to ask any doubts
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