Question

a bicycle increases its velocity from 10km/h to 15km/h in 6 seconds .calculate its accelerations

Answer 1

Acceleration(a) = {Final velocity(v) -Initial velocity(u)} / Time

a = (15km/h - 10km/h) / 6sec
a =(5km/h) / 6 sec
a =(25/18 m/sec) / 6sec
a =25/108 m/s^2

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Answer 2

Aɴꜱᴡᴇʀ

$\huge{\sf\red{a=3.706{ms}^{2}}}$

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Gɪᴠᴇɴ

Initial velocity of bicycle = 10kmph

Final velocity of bicycle = 15kmph

Time interval = 6s

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ᴛᴏ ꜰɪɴᴅ

Acceleration of the bicycle

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Sᴛᴇᴘꜱ

We know that,

Acceleration is defined as ratio of change in velocity to the time interval.

Converstion :-

1kmph = 5/18mps

15kmph = 4.17mps

10kmph = 2.78mps

Then,

$\begin{lgathered} \boxed{\sf\:a=\dfrac{v-u}{t}}\\ \\ \leadsto\sf\:a=\dfrac{4.17-2.78}{6}\\ \\ \dashrightarrow\:{\sf{\pink{\large{a=3.706\:ms^{-2}}}}}\end{lgathered}$

$\large \tt \bigstar{}Additional \: information$

• Acceleration is a vector quantity.

• Accelerataion has both magnitude as well as direction.

• Acceleration can be positive, negative and zero.

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$\huge{\mathfrak{\purple{hope\; it \;helps}}}$