A bicycle
increases its
velocity from lokimin
to 15 km/h in 6 seconds. Calculate
its acceleration.
Answers
Answered by
0
Answer:
0.22 m/s^2
Explanation:
Initial Velocity = u = 10 km/hr
= 10×5 / 18
= 2.77777
= 2.8 m/s
Final Velocity = v = 15 km/hr
= 15×5 / 18
= 4.16 m/s [approx].
Time = t = 6 sec
A = acceleration
Equation of motion :
v = u + at
4.16 = 2.8 + 6a
6a + 2.8 = 4.16
6a = 4.16 - 2.8
6a = 1.36
a = 1.36 / 6
a = 0.22 m/s^2
Hope it helps u .
Attachments:
Answered by
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Here time is given 15 seconds and initial velocity is given 0 May be lokimin means 0. And your final velocity is given 15km/hr .
Explanation:
As we all know that 15km/hr = 25/6metre per second ...
So acceleration = 25/36
HOPE IT'S HELP YOU .
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