Physics, asked by sibunjena045, 8 months ago

A bicycle
increases its
velocity from lokimin
to 15 km/h in 6 seconds. Calculate
its acceleration.​

Answers

Answered by ritanjaliroutray476
0

Answer:

0.22 m/s^2

Explanation:

Initial Velocity = u = 10 km/hr

= 10×5 / 18

= 2.77777

= 2.8 m/s

Final Velocity = v = 15 km/hr

= 15×5 / 18

= 4.16 m/s [approx].

Time = t = 6 sec

A = acceleration

Equation of motion :

v = u + at

4.16 = 2.8 + 6a

6a + 2.8 = 4.16

6a = 4.16 - 2.8

6a = 1.36

a = 1.36 / 6

a = 0.22 m/s^2

Hope it helps u .

Attachments:
Answered by bhagatsumit674
0

Here time is given 15 seconds and initial velocity is given 0 May be lokimin means 0. And your final velocity is given 15km/hr .

Explanation:

As we all know that 15km/hr = 25/6metre per second ...

So acceleration = 25/36

HOPE IT'S HELP YOU .

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