A bicycle initially moving with a velocity 5.0 metre per second for 5 seconds at the rate of 2 metre per second square what will be its final velocity
Answers
Answered by
5
v= u+at
v= 5+(2)(5)
v= 5 +10
v= 15 m/s
hope this helps
v= 5+(2)(5)
v= 5 +10
v= 15 m/s
hope this helps
Athletic:
Thanks bro
Answered by
5
Hey there!
We will use First equation of Motion here,
v = u + at
Here,
u = 5 m/s
a = 2 m/s
t = 5 s
According to the Question,
v = 5 + 2 × 5
v = 5 + 10
v = 15 m/s
Hence, its Final velocity will be 15 m/s
Hope it helped
#EshanSingh1
We will use First equation of Motion here,
v = u + at
Here,
u = 5 m/s
a = 2 m/s
t = 5 s
According to the Question,
v = 5 + 2 × 5
v = 5 + 10
v = 15 m/s
Hence, its Final velocity will be 15 m/s
Hope it helped
#EshanSingh1
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