Question

A bicycle initially moving with a velocity 5m/sec for.....​

Answer 1

Step-by-step explanation:

initial velocity (u)=5m/s

time-5sec

acceleration-5m/s^2

v=u+at

=5+5×5

5+25

30m/s

Answer 2

Answer:-

$\red{\bigstar}$ The final velocity [v] is 30 m/s.

• Given:-

Initial velocity [u] = 5 m/s

Time [t] = 5 sec.

Acceleration [a] = 5 m/s²

• To Find:-

Final velocity [v] = ?

• Solution:-

• Using the 1st equation of motion:-

$\pink{\bigstar}$$\boxed{\sf{v = u + at}}$

here,

u = 5 m/s

a = 5 m/s²

t = 5 sec.

Hence,

→ v = 5 + 5 × 5

→ v = 5 + 25

→ v = 30 m/s

Therefore, the final velocity [v] is 30 m/s.

$\red{\bigstar}$Equations of Motion:-

• 1st equation of motion:-

$\pink{\bigstar}$$\boxed{\sf{v=u+at}}$

• 2nd equation of motion:-

$\pink{\bigstar}$$\boxed{\sf{s=ut+ \dfrac{1}{2}at^{2}}}$

• 3rd equation of motion:-

$\pink{\bigstar}$$\boxed{\sf{v^{2} - u^{2}=2as}}$