Question

A BICYCLE INITIALLY MOVING WITH A VELOCITY OF 10 m/s ACCELERATES FOR 10 sec AT THE RATE OF 4 metre per second square. WHAT WILL BE ITS FINAL VELOCITY?​

Answer 1

Answer:

Initial velocity of the bicycle (u) = 5 m/s Acceleration (a) = 2 m/s^2

Time (t) = 5 sec

Let the final velocity of the bicycle be v. Now, using first equation of the motion:

v = u + at

v = 5 +2 x 5

v = 15 m per sec

Explanation:

Hope this helps you :-)

Answer 2

Provided that:

• Initial velocity = 10 mps
• Time = 10 seconds
• Acceleration = 4 mps sq.

To calculate:

• The final velocity

Solution:

• The final velocity = 50 mps

Using concept:

• First equation of motion

Using formula:

• v = u + at

Where, v denotes final velocity, u denotes initial velocity, a denotes acceleration and t denotes time taken.

Required solution:

~ By using first equation of motion let us calculate the final velocity!

→ v = u + at

→ v = 10 + 4(10)

→ v = 10 + 40

→ v = 50 mps

→ Final velocity = 50 mps $\:$