A BICYCLE INITIALLY MOVING WITH A VELOCITY OF 10 m/s ACCELERATES FOR 10 sec AT THE RATE OF 4 metre per second square. WHAT WILL BE ITS FINAL VELOCITY?
Answers
Answered by
2
Answer:
Initial velocity of the bicycle (u) = 5 m/s Acceleration (a) = 2 m/s^2
Time (t) = 5 sec
Let the final velocity of the bicycle be v. Now, using first equation of the motion:
v = u + at
v = 5 +2 x 5
v = 15 m per sec
Explanation:
Hope this helps you :-)
Answered by
3
Provided that:
- Initial velocity = 10 mps
- Time = 10 seconds
- Acceleration = 4 mps sq.
To calculate:
- The final velocity
Solution:
- The final velocity = 50 mps
Using concept:
- First equation of motion
Using formula:
- v = u + at
Where, v denotes final velocity, u denotes initial velocity, a denotes acceleration and t denotes time taken.
Required solution:
~ By using first equation of motion let us calculate the final velocity!
→ v = u + at
→ v = 10 + 4(10)
→ v = 10 + 40
→ v = 50 mps
→ Final velocity = 50 mps
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