Question

A bicycle initially moving with a velocity of 5.0 metre per second accelerates for 5 seconds at the rate of 2 metre per second square. What will be its final velocity?

Ans:15.0 metre per second​

Answer 1

u = 5

t = 5

a = 2

v= u+ at

= 5 + 5×2

= 15

Answer 2

Answer:

$\huge { \underbrace { \overbrace { \mathfrak{ \orange{hello \: mate}}}}}$

Step-by-step explanation:

given,

initial velocity (u) = 5.0m/s

final velocity (v) = ?

time (t) = 5s

acceleration (a) = 2m/s.

There are two methods of solving this sum,

$\huge \tt \green{first \: method - }$

we know that,

a = (v-u)/t

2 = (v - 5.0) / 5

2×5 = v - 5.0

10 = v - 5.0

v = 10 + 5.0

v = 15.0 or 15 m/s²............

$\huge \tt \green{second \: method - }$

by using the formula,

v = u + at

v = 5.0 + 2×5

v = 5.0 + 10

v = 15.0 / 15m/s²...............

$\mathfrak \red{answer \: =15m{s}^{ - 2}}$