Question

A bicycle initially moving with a velocity of 5.0 ms^-1 accelerates for 5s at the rate of 1ms^-2. How much distance does it cover in 5s?

Answer 1

Explanation:

S = ut + 1/2at^2

S = 5(5)+1/2(1)(5^2)

S = 37.5m

hope you get it.

Answer 2

37.5 m

.

step by step explanation :-

Here,

Initial velocity (u) = 5 m/s

Acceleration (a) = 1 m/s²

Time (t) = 5 s

.

To find -

The distance moved

Solution -

s = ut + 1/2at²

$= > s = (5 \times 5) + ( \frac{1}{2} \times 1 \times {5}^{2} ) \\ = 25 + \frac{25}{2} \\ = 25 + 12.5 \\ = 37.5m$

Hence total distance covered = 37.5 m

hope it helps.