Question

A bicycle list is traveling at 25 m/a when he beings to decelerate at -4m/s^2. How fast is he traveling after five seconds

Answer 1

Initial velocity of the bicycle (u) = 25 m/s

Time taken = 5 seconds

deacceleration = - 4 m/s^2

Let the final velocity be v.

Now, using the first equation of the motion:

v = u + at

v = 25 - 4 × 5

v = 25 - 20

v = 5 m/s

Hence, the final velocity of the bicycle = 5 m/s