A bicycle moves with a constant velocity of 5 km/h for 10 minutes and then decelerates at the rate 1 km/h2, till it stops. Find the total distance covered by the bicycle
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The distance covered in 10 minutes=1/6 hours with velocity of 5km/h
=velocityxtime
=5×1/6
=5/6
By the formula v^2=u^2-2as
the bicycle stops so v=0
and u is given 5kmph
a=1kmph^2
0=5^2-2s
2s=25
s=12.5km
so total distance=
12.5+5/6
=12.5+0.833
=13.333
=velocityxtime
=5×1/6
=5/6
By the formula v^2=u^2-2as
the bicycle stops so v=0
and u is given 5kmph
a=1kmph^2
0=5^2-2s
2s=25
s=12.5km
so total distance=
12.5+5/6
=12.5+0.833
=13.333
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