a bicycle moves with a constant velocity of 5km /h for 10 minutes and then decelerates at the rate 1 km /h ², till it stops . find the total distance covered by the bicycle.
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Answer:
Given,
Initial velocity, u=5Km/h
Time, t=10min=61h
The bicycle is going with constant velocity, a = 0
s=ut+21at2
s=ut
s=5×61
s=65Km..........(1)
In case (2),
u=5Km/h
v=0
a=1Km/h2
Using equation of motion as,
v2−u2=2as
0−(5)2=2(−1)s
s=225Km
Total distance,
=65+225
=13.33Km
Total distance covered by bicycle is 13.33Km.
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