Question

A bicycle moving initially with a velocity 15.0m/s accelerates for 10s at the rate of 4m/s². What will be its final velocity?​

Answer 1

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Given,

$u = 15 \: m {s}^{ - 1} \\ t = 10 \: s \\ a = 4 \: m {s}^{ - 2} \\ v = \: to \: find \: \\ \\ v = u + at \\ \: \: = 15 + 4 \times 10 \\ \: \: = 15 + 40 \\ \: \: = 55 \: m {s}^{ - 1}$

Answer 2

➤ Answer

• Final velocity of the bicycle = 55m/s.

➤ Given

• A bicycle moving initially with a velocity 15m/s accelerates for 10s at the rate of 4m/s².

➤ To Find

• The final velocity of the bicycle.

➤ Step By Step Explanation

Given that ⤵

• Initial velocity = 15m/s
• Acceleration = 4m/s²
• Time = 10s

We need to find final velocity.

So let's do it !!

By using first equation of motion

• v = u + at

By substituting the values

➠ v = 15 + 4 × 10

➠ v = 15 + 40

➠ v = 55 m/s.

Therefore final velocity of bicycle = 55m/s.

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➤ Equations of motion

There are mainly three equations of motion. They are as follows -

• v = u + at
• s = ut + ½at²
• v² - u² = 2as

Where, u = initial velocity , v = final velocity, t = time, a = acceleration, and s = distance travelled.

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