Question

A bicycle rider covers his onward journey from A to B at 10km/hr and during the return journey from B to A he covers the same distance at 8 km/hr. If he finishes the onward and return journey in 4 1⁄2 hours, then the total distance covered by him during the entire journey is ??????????



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Answer 1

$time = \frac{distance}{speed}$

Let the distance from A to B = X

Time required to cover A to B in 10 kmph = x/10

Time required to cover B to A in 8 kmph = x/8

Total time = 4.5 hr

$\frac{x}{10} + \frac{x}{8} = 4.5$

$x = 20 \: km$

Total distance covered by him = 2x = 40 km