Question

A bicycle starts from 5.89 m/s and then come to a stop in 4 s, what is the bicycle’s deceleration?

Answer 1

Answer:

Deceleration = 1.4725 m/s^2

Explanation:

initial velocity (u)=5.89 m/s

Final velocity (v)=0 m/s [ as the body stops ]

time (t)=4 seconds

v=u+at

0=5.89+a(4)

4a=-5.89

a=-1.4725 m/s^2

Hence, Deceleration=1.4725 m/s^2