Question

A bicycle takes 8.0 seconds to accelerate at a constant rate from rest to a speed of 4.0 m/s. If the
mass of the bicycle and rider together is 85 kg, what is the net force acting on the bicycle? (Hint:
first, calculate acceleration)

Answer 1

HEY MATE ...

HERE IT IS.......

this question is based on netwon's second law of motion..
Force = mass x accleration, F = ma
m = 85 kg
a = dv/dt = (0 - 4m/s)/(0 - 8s) = 4/8 m/s^2 = (1/2) m/s^2
F = (85 kg)(1/2)m/s^2 ] = 42.5 k m/s^2


hope it hlps...

Answer 2

Given : A bicycle takes 8.0 seconds to accelerate at a constant rate from rest to a speed of 4.0 m/s. If the

mass of the bicycle and rider together is 85 kg.

To find : The net force acting on the bicycle.

Solution :

42.5 N force is acting on the bicycle.

We can simply solve this numerical problem by using the following process. (our goal is to calculate the net force acting on the bicycle)

First of all, we have to calculate the acceleration.

Now,

Acceleration = (Final velocity - Initial velocity)/Time

Here,

Final velocity = 4 m/s

Initial velocity = 0 m/s (as starts from rest)

Time = 8 seconds

So,

Acceleration = (4-0)/8 = 0.5 m/s²

Now, we also know that :

Force = Mass × Acceleration

Here,

Mass = 85 kg

Acceleration = 0.5 m/s²

So,

Force = 85 × 0.5 = 42.5 kg.m/s² = 42.5 N

(As, 1 kg.m/s² = 1 N)

Hence, 42.5 N force is acting on the bicycle.