Question

A bicycle tire has a diameter of 62 cm. What is the distance the bicycle tire travels in 10 revolutions? Round your answer to the nearest cm.

Answer 1

Hey friend here is ur solution

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Given diameter of bicycle tire= 62 cm = 0.62m


Hence perimeter=π*d

=π*0.62

=1 .95m

Hence travelled distance by bicycle in 10 revolution= 1.95*10
=19.5 meter

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Hope this will help you....

Answer 2

Answer:

Distance the bicycle tire travels in 10 revolutions is 1946.8 cm .

Step-by-step explanation:

Formula

$Circumference\ of\ a\ circle =2 \pi r$

Where r is the radius of the circle .

As given

A bicycle tire has a diameter of 62 cm.

$Radius =\frac{Diameter}{2}$

$Radius =\frac{62}{2}$

                  = 31 cm

$\pi = 3.14$

$Circumference\ of\ a\ circle =2\times 3.14\times 31$

                                                     = 194.68 cm

As given

The bicycle tire travels in 10 revolutions .

Thus

Distance  the bicycle tire travels in 10 revolutions = Circumference of tyre × Number of revolution

                                                                                  = 194.68 × 10

                                                                                  = 1946.8 cm

Therefore distance the bicycle tire travels in 10 revolutions is 1946.8 cm .