Question

A bicycle tire rotates about a fixed axis with an initial angular velocity of 16 rad/s. The angular velocity decreases to 10 rad/s in 4 s. How many radians does the tire turn through during this 4.0-s interval? (Assume the angular acceleration is constant)

How would I do this?

Answer 1

Answer:

-104 rad

Explanation:

here initial acceleration wi = 16 rad/s

final acceleration wf = 10 rad/s

constant acceleration a = (10-16)/4 rad/s² = -3/2 rad/s²

now, dө = {(final acceleration) ²-(initial acceleration)²} / 2a

dө = {(16) ²-(10) ²} / (-3/2) rad

= -(2×156) /3 rad

= -104 rad