A bicycle was travelling at 20ms-1 when it applied it s brakes and decelerated at a rate of 5ms2.How long will it take before it comes to a stop?how far will it travel before stopping?
Answers
Answered by
7
Answer:
Explanation:
u=20m/s
a= -5m/s^2
v=0m/s
t=?
we know,
v=u+at
so,
0=20-5t
hence,
t=4 seconds
s= ut+1/2at^2
= 20x4+1/2x(-5)x16
= 80-40
= 40
lakkepuramy:
s=ut+½at² => s=20(4)-½(5)(4)² = 80-40
Answered by
3
using v=u+at
0=20-5t
20=5t
4=t
therefore it takes 4 seconds to stop.
v²-u²=2as
0-400=-2(5)s
-400=-10s
10s=400
s=40 m
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