Physics, asked by ramsunil7078, 10 months ago

A bicyclist is riding to the left with a velocity of 14 meters for seconds. After a steady gust of wind that last 3.5s, the bicyclist is moving to the left with a velocity of 21 meters per seconds what is the acceleration of the bicyclist

Answers

Answered by rishabhpy3
0

Answer:

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The formula for acceleration = v - u / t

So,

v = 21m

u = 14 m

t  = 3.5 sec

21 - 14 / 3/5 =  7 / 3.5 = 2 m/ s²

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