A big bug ate 54 small bugs in 4 days. each day, it ate 5 more bugs than it did on the previous day. How many small bugs did the big bug eat on 1) the first day 2) the fourth day
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Answer:
1)6
2)21
Step-by-step explanation:
54=x)x+5)x+10)x+15)
X={54-(5+10+15)}÷4
X={54-30}÷4
X=24÷4
X=6
4th day = x+15
4th day=6+15=21
So the bug ate 6 small bugs on the first day
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