Question

A big bug ate 54 small bugs in 4 days . Each day it ate 5more bugs than it did on the previcious day .How many small bugs did the big bug eat on the first day

Answer 1

Answer:

Step-by-step explanation:

Answer 2

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$\to$ 6

$\large \bold{ \underline{ \underline{ \: Explaination : \: \: \: }}}$

Let ,

A big bug ate " x " small bugs on the first day

Each day it ate 5 more bugs than it did on the previcious day so ,

First day = x

Second day = x + 5

Third day = x + 5 + 5

Fourth day = x + 5 + 5 + 5

A.T.Q ,

$\to$ (x) + (x + 5) + (x + 5 + 5) + (x + 5 + 5 + 5) = 54

$\to$ 4x + 30 = 54

$\to$ 4x = 24

$\to$ x = 24 / 4

$\to$ x = 6

Hence , the required number is 6