Question

A big cruise ship dropped anchor off the Caribbean island of Antigua. The heavy anchor dropped into the water at a rate of 2.52.52, point, 5 meters per second. After 454545 seconds, the anchor was 404040 meters below the water's surface.
From what height (above the water's surface) was the anchor rele

Answer 1

Answer:

The anchor was released from a height 72.5 m from the water surface

The time taken in reaching the water surface is 29 seconds

Step-by-step explanation:

Rate of the drop of anchor = 2.5 m/s

In 45 seconds, the anchor will travel the distance

Distance = Speed x Time

or, $d=2.5\times45$

or, $d=112.5$ m

Since it is 40 m below the surface of water

Therefore the height above the surface it was dropped

= d - 40

= 112.5 - 40

= 72.5 m

Time taken in reaching the water surface

= 72.5/2.5

= 29 seconds

Hope this helps.

Answer 2

Answer:7.55

Step-by-step explanation: