Question

A big drop is broken into n³ droplets. What is the work done in doing so​

Answer 1

Answer:

work done = T x delta S

so Surface Area changes when Big droplets is broken to smaller Droplets.

n^3 . v = V. volume conservation

v = V/ n^3

r = R/n

r^2= R^2/ n^2

nr^2= R^2

So , finally Area change = 4Pi nR^2- 4Pi R^2

4Pi(n-1)R^2 is Delta S .

W = 4 pi (n-1)TR^2