a big drop is formed by coalescing 1000 small droplets of water. what will be change in surface energy. what will be ratio between total surface energy of small droplet and big drop
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Explanation:
Solution :
By conservation of volume 43πR3=1000×43πr3imliesr=R10
Surface enegy of 1000 droplets =1000×T×4π[R10]2=10(T×4πR2)
Surface energy of the big drop =T×4πR2
Surface energy will decrease in the process of formation of bigger drop, hence energy is released and temperature
Increases ∴total surface energy of 1000 dropletssurface energy of big drop=10(T×4πR2)T×4πR2=101
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