Question

A big rock with a mass of 20 kg experiences a change in gravitational energy of 120 J as it is lifted up. How high was the rock lifted?
PE = 120Jm = 20 kgg = 9.8 m/s2h = ? mH = PE ÷ (m x g) = 120 ÷ (20 kg x 9.8)= 120 ÷ ______= _____ m H = PE ÷ (m x g)

Answer 1

Answer:

$pe = mgh \\ \\ 120 = 20 \times 9.8 \times h \\ \\ h = \frac{120}{20 \times 9.8} \\ \\ h = 0.6122 \: m$