Question

A bike accelerate uniformly from 18 km/h to 36 km/h in 5sec calculate.
(i) the acceleration of bike ?​

Answer 1

Answer:

Initial velocity, u is given as 18 km/h, So we have to convert it into m/s, For that we have to multiply it with 5/18, So, 18 × 5/18 = 5 m/s.

Answer 2

★ Given That :

• » A Bike accelerate uniformly from 18 km/h to 36 km/h.
• » Time Taken = 5sec

★ Need To FinD :

• » Acceleration of Bike ?

★ Formula UseD Here :

• » a = ( v - u )/t

✠ Where :

• ↪ a = Acceleration
• ↪ v = Final velocity
• ↪ u = Initial velocity
• ↪ t = Time taken

✧ Conversion NeedeD km/h into m/s :

• ⌬ 18km/h into m/s
• ➟ ( 18 × 5 )/18
• ➟ 5m/s [ initial Velocity ]

• ⌬ 36km/h into m/s
• ➟ ( 36 × 5 )/18
• ➟ 5 × 2
• ➟ 10m/s [ Final Velocity ]

⚘ Putting Values in Formula :

• ➣ acceleration = ( v - u ) / t
• ➣ acceleration = ( 10 - 5 ) / 5 m/s²
• ➣ acceleration = 5 / 5 m/s²
• ➣ acceleration = 1m/s²

✇ Therefore :

• ➲ The Acceleration of bike is 1m/s²

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