Question

a bike accelerate uniformly from 72kmph to 180kmph in 5sec.find acceleration, distance travelled by bike
wanr urgent answer pls reply​

Answer 1

Answer:

I hope this is the answer

Explanation:

Let,

Initial velocity(u)=72kmph=20m/s

Final velocity(v)=180kmph=50m/s

Time taken(t) = 5sec

distance travelled=S

Acceleration=a

so to find acceleration we have to use the either 1st or 2nd kinematics but lets use the 1st one.

v=u+at

50=20+a(5)

50-20=5a

30=5a

a=30/5

a=6m/s^2

and to find the distance travelled by the bike we can use either 2nd or 3rd kinematics eq. but lets use the 2nd one

S=ut+1/2(at^2)

S=20(5)+1/2(6(5)^2)               Here a is 6m/s^2

S=100+1/2(6*25)

S=100+1/2(150)

S=100+150/2

S=100+75

S=175meters