Question

A bike accelerate uniformly from rest to a speed of 7.10m/s over a distance of 35.4 m .determine the acceleration of the bike

Answer 1

u=0
v=7.10m/s
s=35.4
v^2-u^2=2as
50.41=70.8a
a=70.8/50.41
a=1.4m/s^2<======Answer

Answer 2

Heya mate ur answer
_________________

U=0
v=7.10
s= 35.4
a=?
v^2-u^2= 2as
(7.10^2-(0)^2= 2×a×35.4
50.41=70.8×a
0.712= a

Hope it helps.....