Question

A bike accelerates from rest and reaches to 40 km/h in 10 s. Calculate 1) Acceleration 2) distance covered by bike In that time.

Answer 1

Given it accelerates from rest, u = 0 m/s

Final Velocity, v = 40 km/h

v = 40 × (5/18) m/s = 100/9 m/s

time taken, t = 10 sec

1) Acceleration :

a = change in velocity upon time

a = ( v – u ) / t

a = ( 100/9 – 0 ) / 10

a = 10 / 9

a = 10/9 m/s²

2) Distance covered by bike :

using second equation of motion

s = ut + 1/2 at²

s = ( 0 ) + 1/2 ( 10/9 ) × ( 10 )²

s = 5/9 × 100

s = 500/9 m

s = 55.5 m

Hope the solution is clear to you!!