A bike accelerates uniformly from 10 m/s to 25 m/s in 5 seconds along a straight line. Find the distance travelled by the bike in this time
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Answer:
Initial velocity (u) = 10 m/s
Final velocity (v) = 25 m/s
Time (t) = 5s
v = u+at
25 = 10+5a
15 = 5a
3 m/s^2 = Acceleration
v^2 = u^2+2aS .... where 'S' stands for Distance
625 = 100+6S
525 = 6S
87.5 m is the distance travelled.
I Hope this helps.
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