Question

A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 m Determine the acceleration of the bike.

Answer 1

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Answer 2

0.712 meter/sec^2

Given:

Initial Velocity (vi) = 0 meter/second

Final Velocity (vf) = 7.10 meter/second

Distance Traveled (s) = 35.4 meters

To Find:

Acceleration = ?

Calculating:

To solve this problem we use the equation of motion:

vf^2 = vi^2 + 2*a*d

Substituting the values known to us in this formula we get:

(7.10)^2 = (0)^2 + 2 x (a)*(35.4)

50.4 = 0 + 2 x a x 35.4

50.4 = 0 + 70.08 x a

50.4 = 70.8a

a = 50.4 / 70.8

a = 0.712 meter/sec^2

Therefore, the acceleration of the bike is 0.712 meter/sec^2.