Question

A bike accelerates uniformly from rest to a speed of 8.00 m/s over a distance of 40.0 m. Determine the acceleration of the bike. ​

Answer 1

a

Explanation:

answer sahi hai to bhaiya bataia

Answer 2

Explanation:

GIVEN

Initial Velocity = 0m/s

Final Velocity = 8.00 m/s

DISTANCE TRAVELED = S= 40.0 m

Let (a) be the acceleration.

USING FORMULA

v² - u²= 2as

= (8.00)² - 0² = 2a (40.0)

a= 5120